If the temperature change is 25°C, how much heat energy in calories is released by 500 grams of water?

To calculate the amount of heat energy released by water when it undergoes a temperature change, you can use the formula:

[ Q = m \times c \times \Delta T ]

where:

• ( Q ) is the heat energy in calories,

• ( m ) is the mass of the water in grams,

• ( c ) is the specific heat capacity of water (which is approximately 1 cal/g°C),

• ( \Delta T ) is the change in temperature in degrees Celsius.

In this scenario:

• The mass ( m ) is 500 grams,

• The specific heat capacity ( c ) of water is 1 cal/g°C,

• The temperature change ( \Delta T ) is 25°C.

Plugging these values into the formula:

[ Q = 500 , \text{g} \times 1 , \text{cal/g°C} \times 25 , \text{°C} ]

Calculating this gives:

[ Q = 500 \times 1 \times 25 = 12,500 , \text{calories} ]

Thus, the correct amount of heat energy released by 500 grams of water when the